求大神数学题

2019-04-29 21:56发布

本人在国外有一题不解,求大神解答
3条回答

[log(4)x -log(4)16]^2+log(4)x -22=0

[log(4)x - 2]^2+log(4)x -22=0

[log(4)x]^2 - 4log(4)x+4+log(4)x -22=0

[log(4)x]^2 - 3log(4)x -18=0

[log(4)x +3][log(4)x-6]=0

log(4)x +3=0 或 log(4)x-6=0

log(4)x =-3 或 log(4)x=6

所以 x0=4^6

3*(4^6)^1/3=3*4^2=3*16=48

所以 选 A)48


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